BRAINLIEST AND 20 PNTS‼️‼️ A 4.03 x 10-5 F capacitor stores
5.15 x 10-3 J of energy. What is the
voltage across the capacitor?

V = 0.06255 Volts

Explanation:

Given the following data;

Capacitance = 4.03 * 10^{-5} F

Energy = 5.15 * 10^{-3} J

To find the voltage across the capacitor;

Mathematically, the energy stored in a capacitor is given by the formula;

E = ½cv²

Where;

C is the capacitor

E is the energy stored

v is the voltage.

Substituting into the formula, we have;

5.15 * 10^{-3} = ½ * 4.03 * 10^{-5} * v²

0.00515 = 0.00002015 * v²

V² = 0.00002015/0.00515

V² = 0.003912

Taking the square root of both sides, we have;

V = √0.003912

V = 0.06255 Volts

16.0 V is the correct answer

Explanation:

answer; equivalent to a one(1) horsepower motor;

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles