Please answer as if you're teaching someone who has no knowledge of the subject, thank you.

(C) 700 N

Explanation:

The given parameters are;

The mass of the mountain climber, m = 100 kg

The angle formed by the rope with the horizontal, θ = 45°

The gravitational field strength, g = 10 N/kg

The weight of the man, W = m × g

∴ W = 100 kg × 10 N/kg = 1,000 N

At equilibrium, we have;

The downward force, the weight of the man, W = The upward force, the vertical component of the tension on the two halves of the rope

We have;

W = T × sin(θ) + T × sin(θ)

∴ 1,000 N = 2 × T × sin(45°)

Therefore, we have;

T = 1,000 N/(2 × sin(45°)) = 707.106781 Newtons

Therefore, the tension in the rope is closest to (approximately) 700 N.

newton's first law of motion