Physics, 04.06.2021 14:00 atkinsonl1076

PLEASE HELP ME WITH THIS ONE QUESTION Given the atomic mass of Boron-9 is 9.0133288 u, what is the nuclear binding energy of Boron-9? (Mproton = 1.0078251, Mneutron = 1.0086649, c^2 = 931.5 eV/u)

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Answer from: gabbym39077

The binding energy is -882.5 MeV.

Explanation:

The nuclear binding energy of Boron-9 can be found as follows:

$B = [Zm_{p} + Nm_{n} - M]c^{2}$

Where:

Z: is the number of protons = atomic number = 5

N: is the number of neutrons = A - Z = 9 - 5 = 4

$m_{p}$ : is the mass of the proton = 1.0078251 u

$m_{n}$ : is the mass of the neutron = 1.0086649 u

M: is the atomic mass of B-9 = 9.0133288 u

c² = 931.5 MeV/u

Hence, the nuclear binding energy is:

$B = [Zm_{p} + Nm_{n} - M]c^{2} = [4*1.0078251 u + 4*1.0086649 u - 9.0133288 u]*931.5 MeV/u = -882.5 MeV$

Therefore, the binding energy is -882.5 MeV.

I hope it helps you!

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