Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce the sound intensity by a factor of 305. If, when the jet is fired up, the sound intensity level experienced by the crew members wearing protective earplugs is 79 dB, determine the sound intensity level they would experience without the earplugs.

the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB

Explanation:

Given the data in the question;

sound intensity reduced by the factor, m = 305

the sound intensity level experienced by the crew members wearing protective earplugs, L = 79 dB

Now, using the expression of sound intensity level;

L = 10log( )

where   is the intensity at L level

so we substitute

79 = 10log( )

=

Now, expression for actual intensity;

= m

where is the actual intensity

so we substitute

= 305 ×

Next, we write the expression of sound intensity level for reduced intensity;

L' = 10log( )

So we substitute

L' = 10log( 305 × )

L' = 10log( 24227011159.09058 )

L' = 103.8 dB

Therefore, the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB

d

explanation:

i think the answer is d. but im not sure!