I need answers fas! If an Electric Field has a strength of 442 N/C and a charge with a magnitude of 5C is placed into it, how much force in N is acting on the charge? Your answer needs to be to the nearest whole number.

the answer for apex is the lowest

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j