Three resistors of values 2 Q, 3 Q and 5 Q are connected in series with a battery of voltage 6.0 V. Calculate the current through each of the resistors, and the current through the battery.

Current = 0.6 A

Explanation:

Given that,

Three resistors 2 ohms, 3 ohms and 5 ohms are connected in series with a battery of voltage 6 V.

In series combination of resistors, the current through each resistor is the same while the voltage divides.

The equivalent resistance in this case is given by :

Put all the values,

Let I be the current. Using Ohm's law,

So, the current through each resistor and the current through the battery is equal to 0.6 A.

ill do it for 100, also this isnt 80 its 40

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