Si un beisbolista lanza una pelota (ver la figura) a una velocidad inicial de (23x5)m/s con un ángulo =70°. Averiguar:

a) La componente horizontal Vx de la velocidad en kilómetros sobre hora (km/h)

b) La componente vertical Vy de la velocidad en kilómetros sobre hora (km/h)

c) Si el ángulo cambia a un ángulo ver la figuraaveriguar la componente Vy si Vx no

cambia (es la misma del punto a)). Ayuda: Despejar h (hipotenusa) de ecuación planteada.

d) Si el ángulo cambia a un ángulo ver la figuraaveriguar la componente Vy si Vx no

cambia (es la misma del punto a)). Ayuda: Despejar h (hipotenusa) de ecuación planteada

(Ayuda: La hipotenusa del triángulo es la velocidad que lleva la pelota.)

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

its c i just checked it

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s