Two experimental runs are performed to determine the calorimetric properties of an alcohol that has a melting point of −10℃. In the first run, a 200-g cube of frozen alcohol, at the melting point, is added to 300 g of water at 20℃ in a styrofoam container. When thermal equilibrium is reached, the alcohol-water solution is at a temperature of 5.0℃. In the second run, an identical cube of alcohol is added to 500 g of water at 20℃ and the temperature at thermal equilibrium is 10℃. The specific heat of water is 4190 J/kg⋅K. Assume that no heat is exchanged with the styrofoam container and with the surroundings. The specific heat of the alcohol is closest to a)2100j/kg. K b)1700j/kg. K c)1900j/kg. K d)2500j/kg. K e)2300j/kg. K

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

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i don't understand. explain it clearly