A particle with a charge-to-mass ratio of 4.8x1011 C/kg starts at rest and is accelerated by 2.6x108 m/s2 over a distance of 1.0 km, after which it maintains constant velocity.
The particle then encounters a magnetic field with a strength of 0.12 mT. Assuming no
other forces are acting on the particle, what is the radius of its path?
Your
0 4.5x103 m
O 4.5x10 m
1.3x10-2 m
O 1.3x10-3 m
Clear answer

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

i do.

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