A ball with a mass of 1.1 kg lies on the floor, a trolley with a mass of 0.60 kg stands on a horizontal table and a weight with a mass of 2.0 kg hangs in the wire according to the figure below. It is 0.3 m from the lowest point of the weight and the floor. Both the ball and the weight are attached to each other via wire that goes through the frictionless pulleys. When the weight falls down, the ball will be lifted and the trolley will move to the left. When the weight hits the floor, it stops, but the cart and ball continue their movement for a short while longer. How high will the ball reach the highest? Ignore friction.

relationships are meaning less your heart will get broken.: (

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

Iwould say i also took the quiz but it didn't show me if i got it correct or not.