A rugby player passes the ball 8.75 m across the field, where it is caught at the same height as it left his hand. At what angle was the ball thrown if its initial speed was 12.0 m/s, assuming that the smaller of the two possible angles was used

θ = 18.3°

Explanation:

The angle can be found by using the formula for the range of projectile motion:

where,

R = Horizontal Range = 8.75 m

u = launch speed = 12 m/s

g = acceleration due to gravity = 9.81 m/s²

θ = launch angle = ?

Therefore,

θ = 18.3°

Since this angle is less than 45°. Therefore, it is the smaller of the two possible angles an dit is the correct

θ = 18.3°

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