Compare the resistance of a 1.5-Amp interior light bulb of a car (operating off a 12-V battery) to the resistance
nce of a 100-Watt bulb operating on a 110-volt household circuitry.

The resistance of the internal light bulb of the car is higher than that of the household circuitry.

Explanation:

Given the following data;

I. Current = 1.5 A

Voltage = 12 V

To find the resistance;

Voltage = current * resistance

12 = 1.5 * resistance

Resistance = 12/1.5

Resistance = 8 Ohms

II. Power = 100 Watt

Voltage = 110 V

To find the resistance;

Power = voltage/resistance²

100 = 110/resistance²

Cross-multiplying, we have;

100resistance² = 110

R² = 110/100

R² = 1.1

Taking the square root of both sides, we have;

R = √1.1

R = 1.05 Ohms

Therefore, the resistance of the internal light bulb of the car is higher than that of the household circuitry.

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