Calculate the electric force between two point charges of -54.0 μC and +36.0 μC when they are 2.00 cm apart. **note -- the metric prefix "micro" = μ = x10 - 6 **

Is this attractive or repulsive?

Can someone help me please? Thank you

43740 N and attractive force

Explanation:

Given that,

Charge 1, q₁ = -54.0 μC

Charge 2, q₂ = +36.0 μC

The distance between charges, r = 2 cm = 0.02 m

We need to find the force between charges. The formula for the force between charges is given by :

Put all the values,

As the charges are opposite, the force between them is attractive. Hence, the required force is 43740 N.

the diagram which shows forces as either balanced = same speed or unbalanced = accelerarting

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.