A spring with a spring constant of 2.00N/m applies a force of 0.500N when it is compressed. How much was the spring compressed? A. 0.250m
B. 4.00m
C. 2.50m
D. 1.00m ​

W= δenergymg = 20.0 nenergy is potential energy.w = δek = mgh = (20.0 n) * 1.50 m = 30.0j30.0 j is done on the object.

The answer would be true, hope this ! : )

The answer is the same momentum

The elastic potential energy of a spring is computed by: 1/2 * k * x^2where: k = spring constant = 46 n/m  x = displaced length = 0.146 - 0.116 = 0.03  m = 3 cm  pe = 0.5*46*.023^2 = 0.012167 j = 12.17 mj is the elastic potential energy stored in the spring.