A golf ball leaves a golf club with an initial velocity of 40.0 meters per second at an angle of 40.°
with the horizontal.
Vi = 49.0 m/s
40.0
What is the vertical component of the golf ball's initial
velocity?

Imagine an isolated positive point charge q (many times larger than the charge on a single proton). there is a charged particle a (whose charge is much smaller than charge q) at a distance from the point charge q. on which of the following quantities does the magnitude of the electric field created by charge q at particle a's position depend? check all that apply.the type of the charge on the charged particle athe relative orientation between q and a (while the distance between q and a is fixed)the specific location of the charged particle a (while the distance between q and a is fixed)the amount of the charge on the point charge qthe specific location of the point charge q (while the distance between q and a is fixed)the distance between the point charge q and the charged particle athe amount of the charge on the charged particle a

1. study the scenario. the particles in some system are moving around quickly. a few minutes later, the particles are moving, on average, more slowly. how does this change in motion affect the temperature of the system? the temperature of the system did not change. the speed of the particles does not affect temperature, the number of particles affects the temperature.the temperature of the system is lower now than it was initially. faster moving particles result in a higher temperature for the system.the temperature of the system is higher now than it was initially. slower moving particles result in a higher temperature for the system.the temperature of the system did not change. the speed of the particles has no effect on the temperature, only the type of atom affects the temperature.

Aparticle is moving around in a circle and its position is given in polar coordinates as x = rcosθ, and y = rsinθ, where r is the radius of the circle, and θ is in radians. from these equations derive the equation for centripetal acceleration.