A 0.25 m long wire carries a 12 A current west. Earth's magnetic field at that point is 4.8E-5 T to the north. What is the magnitude of the force in the wire?
A) 2.3E-5 N
B) 1.4E-4 N
C) 2.3E-3N
D) 1.4E-2N

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.