A force is applied to a 12 kg box. The force is applied parallel to the motion of the box. Determine the force acting on the box if it moves 22 meters and increases the box’s speed from 10 m/s to 25 m/s.

Force = 143.16 Newton

Explanation:

Given the following data;

Distance, S = 22 m

Initial velocity, U = 10 m/s

Final velocity, V = 25 m/s

Mass = 12 kg

To find the force acting on the box;

First of all, we would determine the acceleration of the box using the third equation of motion;

V² = U² + 2aS

25² = 10² + 2*a*22

625 = 100 + 44a

625 - 100 = 44a

525 = 44a

Acceleration, a = 525/44

Acceleration, a = 11.93 m/s²

Next, we find the force;

Force = mass * acceleration

Force = 12 * 11.93

Force = 143.16 Newton

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.