PHYSICS QUESTION! NEED HELP ASAP! Part 1:

The index of refraction for silicate flint glass

is 1.66 for light with a wavelength of 400 nm.

Find the angle of refraction for light with

wavelength 400 nm that is incident on this

glass at an angle of 51◦.

Answer in units of ◦.

Part 2:

The index of refraction for silicate flint glass

is 1.61 for light with a wavelength of 700 nm.

Find the angle of refraction for light with

wavelength 700 nm that is incident on this

glass at an angle of 51◦.

Answer in units of ◦.

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    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s