A hollow Spherical conductor of radius 12 cm is charged to 6x10^-6 c. Find the electric field
Strength at the surface of sphere inside the sphere
at 8 cm and at distance 15m from the sphere.​

Explanation:

Radius of the charged sphere (R)=12cm

Charge (q)=6∗10^−6C

Electric field intensity (E)=?

i) On the surface

ii) Inside the sphere,

E=0;  Because charge enclosed by Gaussian surface is zero.

iii) Outside the sphere at distance 15cm

i.e. r=12+15=27cm=0.27m

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