A vehicle is travelling with uniform velocity along a straight, level stretch of highway. The combined force due to the rolling friction and air resistance is - 5000 N. What is the applied force on the vehicle as it moves?

The applied force on the vehicle is 5,000 N

Explanation:

From the question, we have the following parameters of the motion of the vehicle;

The form of the velocity with which the vehicle is travelling = Uniform velocity

The direction of motion of the vehicle = Along a straight and level stretch of the highway

The combined force which acts as resistance to the vehicle's motion = 5,000 N from rolling friction and resistance of the air opposite to the direction of motion

A vehicle travelling with uniform velocity has zero acceleration, therefore;

The acceleration of the vehicle, a = 0 m/s²

According to Newton's Second Law of Motion, we have;

Force, F = Mass, m × Acceleration, a

∴ The net force of acting on the vehicle, F = m × a

Where;

m = The mass of the vehicle

a = The acceleration of the vehicle = 0 m/s²

∴ F = m × 0 = 0

The net force on the vehicle = 0, therefore;

The applied force + The force of rolling friction and air resistance = 0

We therefore have;

The applied force + 5,000 N = 0

∴ The applied force = 0 - 5,000 N = -5,000 N

The applied force, F = 5,000 N in the direction of motion.

6/12=1/2

step-by-step explanation:

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