A car is travelling at 27m/s and decelerates at a=5m/s2 for a distance of 10m. Calculate its final velocity. (Hint does deceleration imply that the acceleration is positive or negative?)

If deceleration = 5 m/s²

then acceleration = -5 m/s²

According to third law of motion,

= v² = 2as + u²

= v² = 2×-5×10 + 27²

= v² = -100 + 729

= v =√ 629

= 25.08 m/s

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.