What is the combined resistance of 5ohms wire arranged in series with a parallel arrangement of 4ohms and 6ohms wires No link or I'll report you

This is a very straightforward problem, and not too difficult to do in your head. If we have two nearly equal resistances, the series resistance (Rs) is twice the average value (midpoint between the two) and the parallel resistance Rp) is approximately equal to half the midpoint value. So a rough initial guess might be 12 and 13 ohms, where Rs is 25 ohms but Rp is approximately 6.25 ohms. Since Rp needs to be lower, we can play around with resistor values. Here’s an easy shortcut:

Let’s start with the equation for two parallel resistors:

Rp = (R1 * R2)/(R1 + R2)

Since Rs = R1 + R2,

Rp = (R1 * R2)/Rs.

We can rewrite this as

Rp * Rs = R1 * R2

Plugging in our numbers (Rp = 6, Rs = 25), we see that R1 + R2 = 150. What two numbers in the vicinity of 12 and 13 have the product of 150 and a sum of 25? Immediately 10 and 15 come to mind! Easy enough!

d) physical means can be used to separate the components of air.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this