A girl who has a mass of 45kg slides down a slide that is inclined at an angle of 45° with the horizontal if the coefficient of kinetic friction between the girl and the slide is 0.25 what is the magnitude of her acceleration? Plz if Somone can write the steps thanks ​

acceleration is equal to 318.195

Explanation:

a=mgsinø

=45*10sin45⁰

=450*0.7071

=318.195

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards