PLEASE HELP ME WITH THIS ONE QUESTION A test charge of +5e is brought into an electric field of strength of 5.0 x 10^-5 N/C at a distance from the source of 10 centimeters. What is the electrostatic force on that test charge? (Coulomb’s constant is 9.0 × 10^9 Nm^2/C^2; e = -1.602 x 10^-19 C)

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current

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