In Figure 4.40, a person skis down a 20 m long snow slope which makes an angle of 25° with the horizontal
The total mass of the skier and skis is 50 kg. A constant
frictional force of 60 N opposes the skier's motion. The
speed of the skier descending from the top of the slope
is 2.5 ms.
a) Calculate the magnitude of the net force parallel
to the slope experienced by the skier.
b) Use the work-energy theorem to calculate the
maximum speed of the skier at the bottom of the
20 m long slope.
monline​

10 is the . . .

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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