A negative charge of - 0.0005 C exerts an attractive force of 7.0 N on a second charge that is 10 m away. What is the magnitude of the second charge?

This is the answer of your question

Ibelieve the answer is either b or c, but i'm leaning more towards c.hope my answer has you : )

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.