A resonating glass tube closed at one end is 3.6 cm wide and 31.2 cm long. What are the frequencies of the first two harmonics for the resonating tube? The speed of sound in air at this temperature is 351 m/s. Group of answer choices

2.81 Hz, 8.43 Hz

281 Hz, 562 Hz

281 Hz, 843 Hz

562 Hz, 1686 Hz

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Iwould have to say sorry i can't elaborate more. hope this though!