Physics, 18.12.2019 18:31 nofer

Give two examples of when you would need to use the measure skill in science?

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Answer from: gg68814

I'm guessing "measure skill" means "the ability to measure things." In reality, all experiments by necessity require data and typically we need to measure things to get them (even if this is done by devices, programs or computers). When doing science labs, you'll likely need to use scales, pipets, and various glasswear to measure different things. Even if you're used to using a ruler, getting a really good measurement that you can feed into equations and get meaningful results from requires a bit of practice and more care than you might think. I'd also say that the measurement skill comes into play when making approximations or assumptions about experiment. No measurement is infinitely accurate, you can't measure the width of an atom with a standard 12 inch ruler, or if you did, you'd have to have a very large amount of error. Making these logical conclusions about your devices, where they reach their limits, and what potential error you may have and where it comes from are all important when doing science.

Answer from: CaylaJosephinee

We have that the two examples of when you would need to use the measure skill in science

Interpreting DrawingsSurvey

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Two examples of when you would need to use the measure skill in science

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Interpreting Drawings

In Engineering as a branch of science it Measuring is use on a day to day basis where engineering are require to upscale measurements done on a small scaled drawing.

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Measurement is the mean idea of this This Civil Engineering branch of science that dwells meanly on measuring land and spaces in general

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Answer from: Quest

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Answer from: Quest

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !

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