Electromagnetic radiation with a wavelength of 445 nm appears as blue light to the human eye. the energy of one photon of this light is j.

To determine the energy of a light that is being emitted, we need a relation that would relate to the wavelength of the light. For this case, we use the equation E = hc/λ where h is the Planck's constant and c is the speed of light and λ is the wavelength of the light. Planck's constant is equal to 6.626x10^-34 m^2 kg/s and speed of light is 3x10^8 m/s. The wavelength is 445 nm or 445x10^-9 m.

Energy of one photon = 6.626 x 10^-34 m^2 kg/s (3 x 10^8 m/s) / 445 x 10^-9 = 4.47 x 10^-19 J

Therefore the energy of the light is 4.47 x 10^-19 J.

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge