Amass of 1 slug, when attached to a spring, stretches it 2 feet and then comes to rest in the equilibrium position. starting at t = 0, an external force equal to f(t) = 8 sin 4t is applied to the system. find the equation of motion if the surrounding medium offers a damping force that is numerically equal to 8 times the instantaneous velocity.

1 slug = 32 lb 

f = kx 
32 = k(2) 
k = 16 

c = 8 ( 8 times the instantaneous velocity) 

mx'' + cx' + kx = 8sin4t 
x'' + 8x' + 16x = 8sin4t 

Find for the complimentary solution xh:
r² + 8r + 16 = 0 
r² + 4r + 4r + 16 = 0 
(r + 4)(r + 4) = 0 
r = -4, -4 (repeated roots) 
xh = c₁e^(-4t) + c₂te^(-4t) 

Find for the particular solution xp:
xp = Acos(4t) + Bsin(4t) 
xp' = -4Asin(4t) + 4Bcos(4t) 
xp'' = -16Acos(4t) - 16Bsin(4t) 
x'' + 8x' + 16x = 8sin(4t) 
-16Acos(4t) - 16Bsin(4t) + 8[ -4Asin(4t) + 4Bcos(4t) ] + 16 [ Acos(4t) + Bsin(4t) ] = 8sin(4t) 
-16Acos(4t) - 16Bsin(4t) - 32Asin(4t) + 32Bcos(4t) + 16Acos(4t) + 16Bsin(4t) ] = 8sin(4t) 
-32Asin(4t) + 32Bcos(4t) = 8sin(4t) 
-4Asin(4t) + 4Bcos(4t) = sin(4t) 

We group like terms and then solve for A and B:
4Bcos(4t) = 0 
B = 0 

-4Asin(4t) + 4Bcos(4t) = sin(4t) 
-4Asin(4t) = sin(4t) 
A = -¼ 

xp = Acos(4t) + Bsin(4t) 
xp = -¼cos(4t) + (0) sin(4t) 
xp = -¼cos(4t) 

The general solution is therefore: 
x(t) = xh + xp 
x(t) = c₁e^(-4t) + c₂te^(-4t) - ¼ cos(4t) 

at t = 0 it starts from rest that is initial velocity = 0 
x'(0) = 0 

at t = 0 it starts from equilibrium 
x(0) = 0 

x(t) = c₁e^(-4t) + c₂te^(-4t) - ¼cos(4t) 
0 = c₁ + c₂(0) - ¼cos(0) 
c₁ = ¼ 

x(t) = c₁e^(-4t) + c₂te^(-4t) - ¼cos(4t) 
x(t) =¼e^(-4t) + c₂te^(-4t) - ¼cos(4t) 
x '(t) = -e^(-4t) + [ -4c₂te^(-4t) + c₂e^(-4t) ] + sin(4t) 
x '(t) = -e^(-4t) - 4c₂te^(-4t) + c₂e^(-4t) + sin(4t) 

x'(0) = 0 
0 = -e^(0) - 4c₂(0) e^(0) + c₂e^(0) + sin(0) 
0 = -1 + c₂ + 
= -4c₁ - 4c₂(0) + c₂ 
0= -4(1/4) + c₂ 
c₂ = 1 

x(t) =¼e^(-4t) + c₂te^(-4t) - ¼cos(4t) 
x(t) =¼e^(-4t) + te^(-4t) - ¼cos(4t) 

the assestment will probley apele with cause and effect

we need to know the time interval during which the force acts. impulse of force = momentum change