The net force on a car is zero in both the horizontal and vertical directions. which two situations could be true about the motion of the car?
1.the car is speeding up onto the highway.
2.the car is parked.
3.the car is moving at a fixed speed and direction.
4.the car is braking (slowing down).
5.the car is being struck by another car.

Option 2 and 3

Explanation:

When the net force on the car is zero, the acceleration is also zero.

Along horizontal direction, the net force is zero. It means the car is moving with fixed speed and same direction.

Along vertical direction, the weight of the car is balanced by the normal reaction.

When the car is parked, the weight of the car is balanced by the normal reaction.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.