Urgent ! a spring has a spring constant of 105 n/m. if you compress the spring 0.1 m past its natural length, what force does the spring apply? a. 500n, b. 10.5n, c. 0.0005n, d. 1050n

Force, F = -10.5 N

Explanation:

It is given that,

Spring constant of a spring, k = 105 N/m

The compression in the spring, x = 0.1 m

We need to find the force applied by the spring. We know that the Hooke's law gives the relationship between the force and the compression in the spring. It is given by :

F = -kx

F = -10.5 N

So, the force applied by the spring is 10.5 N. Hence, this is the required solution.

it was given as a lesson and guide for prayer.

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..