If a 65-kg man undergoes a turning acceleration of 5 m/s2 during a running turn, what is the magnitude of force experienced by the foot due to the ground?

Force, F = 715.11 newton

Explanation:

Given that,

Mass of the person, m = 65 kg

Acceleration of man during a running turn,

We need to find the magnitude of force experienced by the foot due to the ground. It can be calculated using second law of motion as :

F = ma

F = 325 Newton

Here, the weight of the person and this force force a right angle triangle.

The wight of the person, W = mg

So, the resultant for is,

So, the f force experienced by the foot due to the ground is 715.11 newtons. Hence, this is the required solution.

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered