Arubber band has potential energy of 5 j. if the spring constant of the rubber band is 50 n/m, what is the displacement of the rubber band?

To determine the displacement, since we are given the potential energy, we use the equation for potential energy. For a spring, it is one-half the product of the spring constant and the square of the displacement. We do as follows:

PE = kx^2/2
5 Nm = 50N/m (x^2)
x = 0.32 m

Therefore, the displacement would be 0.32 m.

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