If you throw a ball upward with an initial speed of 4m/s at 1.5m above the ground, find
a. the flying time for this free fall motion,
b. the final velocity just before touching the ground, and
c. the maximum height with respect to the ground.

A. Using the equations

"V final(Vf) = V initial(Vo) + acceleration(a) * time(t) 
delta x(or y) = Vot + 1/2at^2 
Vf^2 = Vo^2 + 2adelta(x)"

Vf is 0 
Vo is 4 
a is -9.8 
delta y = is missing 

Vf^2 = Vo^2 + 2adelta(x) 

0 = 16 + 2(-9.8)delta y 
y= .816 
C= 2.316m 

Vf^2 = 2 (9.8) 2.316 
Vf = 6.738 m/s 

B.

V final(Vf) = V initial(Vo) + acceleration(a) * time(t) 

Vf = part B 
Vo = 0 
a = 9.8 
t = ? 

t = .687s from the top to the bottom but you have to account for it going up too 

C. 
And using the equation again should you get:
t = .408s 

total = 1.096s

10 is the . . .