Two charges attract each other with a force of 1.5 n. what will be the force if the distance between them is reduced to one-ninth of its original value?

Explanation:

The force between two charges is, F = 1.5 N when they are r distance apart such that,

.......(1)

We need to find the force F' if the distance between them is reduced to one-ninth of its original value, r' = r/9

..........(2)

Dividing equation (1) and (2) we get:

F' = 121.5  N

So, the new force is 121.5  N when the distance between them is reduced to one-ninth of its original value. Hence, this is the required solution.