An elevator is moving upward at 1.20 m/s when it experiences an acceleration of 0.31 downward over a distance of 0.75m. what will its final velocity be?

The final velocity is 0.99 m/s.

Explanation:

Given that,

Speed = 1.20 m/s

Acceleration = -0.31 m/s²

Distance = 0.75 m

We need to calculate the final velocity

Using equation of motion

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value in the equation

Hence, The final velocity is 0.99 m/s.

b

explanation: