Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0°. if the ball moves through the air for 3.2 seconds, what is the horizontal distance traveled by the ball? round your answer to the nearest tenth.

Answer

27.7

Explanation

The ball was hit at an angle of 30°, with the horizontal at a speed of 10 m/s. We have to find the horizontal component of speed.

cosx = adjacent/hypotenuse

cos 30 = adjacent / 10

adjacent = 10 cos30

             = 8.66 m/s        ⇒ This is the horizontal speed.

Now  find the horizontal distance.

Distance = speed × time

               = 8.66 × 3.2

                = 27.71

Answer to the nearest tenth = 27.7