Tony is driving a truck of mass 2.00 × 103 kilograms to the west with a velocity of 14.0 meters/second. he collides with a car of mass 1.20 × 103 kilograms moving to the south with velocity 21.0 meters/second. after the collision, they move together. find the velocity with which they move together.

11.7 m/s

Given:

M1 = 2,000kg, V1 = 14.0m/s

M2 = 1200kg, V2 = 21.0m/s

V3 = Velocity of M1, and M2 after colliding.

Momentum before = Momentum after.

M1×V1 + M2×V2 = M1*V3 + M2*V3.

2000×14  + 1200×21 = 2000V3 + 1200V3,

28,000+ 25,200= 3200V3,

Divide both sides by 3200:

V3 = 8.75 + 7.875 = -8.75 - 7.875i

  = 11.77 m/s

The common velocity will be  11.77m/s, in the south west direction.

explanation:

newton's third law, for every action there is an equal and opposite reaction.