A20.0 kg object is at rest, and then speeds up to 16.0 m/s. how much work was done on this system?

Answer : Work done, W = 2560 J.

Explanation :

It is given that,

The mass of an object, m = 20 kg

Initial speed of the object, u = 0

Final speed of the object, v = 16 m/s

We know that the work done by an object is equivalent to the change in kinetic energy.

So,

So, the work done on this system is 2560 J.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards