It takes 250 n to pull a longbow 0.60 m. if all the energy required to pull the bow back is delivered to the arrow, what would be the kinetic energy of the arrow when it is fired? assume the bow behaves according to hooke's law.

Here, arrow gains kinetic energy because of work done by bow. The bow acts as spring. When pulled back, all the energy is stored in bow in the form of potential energy and when it's released, potential energy is converted into kinetic energy.
According to work-energy theorem,
Work done by all forces = change in kinetic energy.
F.x = (K.E)f - (K.E)i = (K.E)f -0
250×0.6 = (K.E)f
(K.E)f = 150 J.

Uncle grandma