How much heat is absorbed by a 35g iron skillet when its temperature rises from 14oc to 79oc? joules

Data:
Q (Amount of heat) = ?(in Joule)
m (mass) = 35 g
c (Specific heat of iron) = 0.45 J/(g × ° C)
T (final) = 79 ºC
To (initial) = 14 ºC
ΔT = T - To → ΔT = 79 - 14 → ΔT = 65 ºC

Formula:
Q = m*c*ΔT

Solving:
Q = m*c*ΔT
Q = 35*0.45*65

26.4 is about the right time

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