A1.50-kilogram ball is attached to the end of a 0.520-meter string and swung in a circle. the velocity of the ball is 9.78 m/s. what is the tension in the string? 74.6 n 276 n 28.2 n 3.39 n

The tension in the string is 276 N.

Explanation:

It is given that,

Mass of the ball, m = 1.5 kg

Length of the meter stick, r = 0.52 m

Velocity of the ball, v = 9.78 m/s

The tension acting in the string is balanced by the centripetal force acting on it. Its formula is given by :

or

So, the tension in the string is 276 N. Hence, this is the required solution.

option number c is the right answer.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2