A70.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45.0° with the mast. how much work did he do?

He did 10198.5 J of work.

Explanation:

As it is given in the problem, A 70.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45.0° with the mast.

Calculate the force.

Here, m is the mass and g is the acceleration due to gravity.

Put m= 70.0 kg and g=9.8 meter per second.

Use the formula for the work done.

Here, F is the force, s is the displacement and is the angle between the force and displacement.

Put F=686 N, s=28.3 m and  =45.0°.

Therefore, he did 10198.5 J of work.

we need to know the time interval during which the force acts. impulse of force = momentum change

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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