Arugby player passes the ball 7.00 m across the field,
where it is caught at the same height as it left his hand. at
what angle was the ball thrown if its initial speed was 12.0 m/s? (in degrees)

The horizontal distance between the origin and the final destination of a projectile is referred to as the range of the projectile. This can be calculated through the equation,
                               R = v₀²sin2θ / g
where R is the range, v₀  is the initial velocity, θ is the angle and g is the acceleration due to gravity. 
Substituting the known values from the given above,
                            7 = (12 m/s)²(sin2θ) / 9.8 m/s²
The value of θ from the equation is 14.22°.

Depotion can i think