The electric field in a 3.0mm×3.0mm square aluminum wire is 1.0×10−2 v/m . what is the current in the wire?

So here is my answer. Given that the electric field in a 3.0mm×3.0mm square aluminum wire is 1.0×10−2 V/m, this is how we find the current in the wire.
First, we take the distance as 3mm or 0.003m. Using the formula E=V/d, where d is distance, v voltage and E electric field strength, we make V the subject, being V=Ed or 2.2*10^-2*0.003=6.6*10^-5V
Hope this answers your question.

Ithink they do have the same properties just in less quantities i think

To use anything transparent