The distance versus time plot for a particular object shows a quadratic relationship. which column of distance data is possible for this situation? time (s) a. distance (m) b. distance (m) c. distance (m) d. distance (m) e. distance (m) 0 0 2.00 9.00 ‡ ‡ 1 1.00 4.00 18.00 1.00 1.00 2 4.00 6.00 27.00 0.50 0.25 3 9.00 8.00 36.00 0.33 0.11 4 16.00 10.00 45.00 0.25 0.06 5 25.00 12.00 54.00 0.20 0.04 6 36.00 14.00 63.00

COLUMN A

Explanation:

The distance versus time plot for a particular object shows a quadratic relationship. Which column of distance data is possible for this situation? Time (s) A. Distance (m) B. Distance (m) C. Distance (m) D. Distance (m) E. Distance (m) 0 0 2.00 9.00 ‡ ‡ 1 1.00 4.00 18.00 1.00 1.00 2 4.00 6.00 27.00 0.50 0.25 3 9.00 8.00 36.00 0.33 0.11 4 16.00 10.00 45.00 0.25 0.06 5 25.00 12.00 54.00 0.20 0.04 6 36.00 14.00 63.00

A quadratic relation mean one variable is proportional to the square of the other variable.

for this problem, distance and time will be proportional to the following equation

d = kt²

or

t = kd²

where k is a (constant).

when y look  at  column A closely .  The numbers are all perfect squares: 1, 4, 9, 16...

This means d = kt²  with k=1:

at t = 0, d = 1 x 0² = 0

at  t = 1, d = 1 x 1² = 1

at  t = 2, d = 1 x 2² = 4

at   t = 3, d = 1 x 3² = 9

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.