Aping-pong ball has a mass of 2.3 g and a terminal speed of 9.1 m/s. the drag force is of the form bv2 what is the value of b?

Explanation:

The terminal speed is reached by an object in free fall when the force of gravity becomes equal to the air resistance:

This can be rewritten as

where

m is the mass of the object

g is the gravitational acceleration

b is the coefficient of the air resistance

v is the speed of the object

In this problem, we have m = 2.3 g = 0.0023 kg, g=9.8 m/s^2 and v=9.1 m/s. Substituting and re-arranging the equation we find

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000