A1.0 kg brick falls off a ledge of height 44m and lands on the ground at 3.0 s later.
a. find the final velocity of the brick using equations of motion
b. find the final velocity of the brick using conversation of energy

vf^2 = 2ad
vf^2 = 2(9.81)(44m)
vf^2 = 863.28
vf = √863.28
vf = 29.4  - using equations of motion

ME = PE + KE
ME = mgh + 1/2mv^2
ME = (1)(9.81)(44) + 1/2(1)(3^2)
ME = 431.64 + 4.5
ME = 436.14 - using conservation of energy

hope this helps :)

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