If a lamp has a resistance of 136 ohms when it operates at a power of 1.00 × ^2, what is the potential difference across the lamp?

Given resistance in ohms and current in ampere, the power can be calculated by the equation,
                                      P = I² x R
where I is current, P is power, and R is resistance
Substituting the given values,
                            1.00 x 10² = (I²) x 136 ohms ;   I = 0.8575 amp
Then, by Ohm's law, the value of V = I x R. Substituting,
                                       V = (0.8575 amp) x (136 ohms) = 116.619 volts
Thus, the potential difference across the lamp is approximately equal to 116.619 volts. 

English can you write this in english do we can you

The car would move to the right with 150 n of force. the 150 n of force from friction and air resistance slows the car from moving to the right with 300 n of force.